设f’(x)=arcsin(x-1)2及f(0)=0,求∫01f(x)dx.

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问题 设f’(x)=arcsin(x-1)2及f(0)=0,求∫01f(x)dx.

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答案I=∫01f(x)dx=xf(x)|01-∫01xf’(x)dx=f(1)-∫01xarcsin(x-1)2dx,(*) 而f(1)=∫01f’(x)dx-f(0)=∫01arcsin(x-1)2dx, 代入(*)式得 I=∫01(1-x)arcsin(x-1)2dx 令t=x-1,则 [*]

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