设z=f(x,y)由方程z—y—x+xez-y-x=0确定,求dz.

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问题 设z=f(x,y)由方程z—y—x+xez-y-x=0确定,求dz.

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答案对z—y—x+xez-y-x=0两边求微分,得dz一dy—dx+ez-y-xdx+xez-y-x(dz—dy-dx)=0,解得dz=[*]dx+dy.

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