admin2022-08-19  50

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答案因为(x2ex)′(x2+2x)ex, 所以∫[(x+2)/x(1+x2ex)]dx=∫[(x2+2x)ex]/[x2ex(1+x2ex)]dx=∫[1/x2ex(1+x2ex)]d(x2ex) =∫[1/x2ex-1/(1+x2ex)]d(x2ex)ln[x2ex/(1+x2ex)+C.

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