设f(x)满足等式xf’(x)-f(x)=,且f(1)=4,则∫01f(x)dx=______.

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问题 设f(x)满足等式xf’(x)-f(x)=,且f(1)=4,则∫01f(x)dx=______.

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答案[*]

解析01f(x)dx=xf(x)|01-∫01xf’(x)dx=f(1)-∫01[f(x)+
]dx
=4-∫01f(x)dx+∫01d(1-x)
=4-∫01f(x)dx-∫01dt=4-∫01f(x)dx-cos2θdθ
=4-∫01f(x)dx-
于是∫01f(x)dx=2-
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