求∫02adx(x+y)2dy(a>0).

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问题 求∫02adx(x+y)2dy(a>0).

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答案令[*](0≤θ≤[*],0≤r≤2a cosθ},则 ∫02adx[*](x+y)2dy=[*]dθ∫02acosθr3(sinθ+cosθ)2dr =4a4[*](1+2sinθcosθ)cos4θdθ =4a4[*]cos4θdθ+8a4[*]sinθcos5θdθ [*]

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