求微分方程(3x2+2xy-y2)dx+(x2-2xy)dy=0的通解.

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问题 求微分方程(3x2+2xy-y2)dx+(x2-2xy)dy=0的通解.

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答案用凑全微分的方法求解.由于 (3x2+2xy-y2)dx+(x2-2xy)dy =3x2dx+[yd(x2)+x2dy]-[y2dx+xd(y2)] =d(x3)+d(x2y)-d(xy2) =d(x3+x2y-xy
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