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答案ln(1+χ)ln(1-χ)-ln(1-χ2)=ln(1+χ)ln(1-χ)-ln(1+χ)(1-χ) =ln(1+χ)[ln(1-χ)-1]-ln(1-χ), 由ln(1+χ)=χ-[*]+o(χ4), ln(1-χ)=-χ-[*]+o(χ4)得 ln(1+χ)[ln(1-χ)-1] [*] ln(1+χ)[ln(1-χ)-1]-ln(1-χ)~[*] 故[*]

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