求:

admin2020-03-10  140

问题 求:

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答案(1)因为cosx=1-[*]x4+o(x4),[*]+o(x4), 所以[*]x4+o(x4)=[*]x4+o(x4), 则 [*] (2)cos(sinx)=[*]+o(x4) sin2x=[x-[*]+o(x3)]2=x2-[*]+o(x4), sin4x=[x-[*]+o(x3)]4=x4+o(x4), cos(sinx)=1-[*]+o(x4), cosx=1-[*]+o(x4), 则cos(sinx)-cosx~[*]x4, 故 [*]

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