2. 考研
  3. 设为曲面z=√(x2+y2)(1≤x2+y2≤4)下侧，f(x)为连续函数．计算I=[xy(xy)+2x-y]dydz+[yf(xy)+2y+x]dzdx+[zf(xy)+z]dxdy

设为曲面z=√(x2+y2)(1≤x2+y2≤4)下侧，f(x)为连续函数．计算I=[xy(xy)+2x-y]dydz+[yf(xy)+2y+x]dzdx+[zf(xy)+z]dxdy

admin2020-04-07  25
问题 设为曲面z=√(x2+y2)(1≤x2+y2≤4)下侧，f(x)为连续函数．计算I=[xy(xy)+2x-y]dydz+[yf(xy)+2y+x]dzdx+[zf(xy)+z]dxdy
选项
答案[*]
解析
转载请注明原文地址:https://kaotiyun.com/show/aKS4777K
0

考研数学一

相关试题推荐
随机试题
最新回复(0)