设函数z=f(x,y)(xy≠0)满足f(xy,)=y2(x2一1),则dz=__________.

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问题 设函数z=f(x,y)(xy≠0)满足f(xy,)=y2(x2一1),则dz=__________.

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答案(2x—y)dx—xdy

解析 设xy=u,,y2=uv,则
    f(u,v)=uv(一1)=u2一uv,
    即    f(x,y)=x2一xy.
    所以dz=(2x—y)dx—xdy.
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